The point: quadrant and projections

Given point P(4, 25, 18), state its quadrant or special case and draw its horizontal projection P′ and vertical one P″.

Step-by-step solution

P′ is obtained by keeping X and Y and setting height 0: the projection on the PH.
P″ is obtained by keeping X and Z and setting distance 0: the projection on the PV.
Check the quadrant: height 18 and distance 25.

Result: in the first quadrant. P′(4, 25, 0) and P″(4, 0, 18). It is above the PH and in front of the PV.

Height decides whether it is above or below the PH; distance, whether it is in front of or behind the PV.